# Applying the Quadratic Formula (Part 1)

ID: gimab-takin Illustrative Mathematics, CC BY 4.0
Subject: Algebra, Algebra 2
Standards: HSA-REI.B.4HSA-REI.AHSA-CED.A.1HSA-REI.B.4.bHSF-IF.B.5

14 questions

# Applying the Quadratic Formula (Part 1)

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##### No Solutions for You!

Here is an example of someone solving a quadratic equation that has no solutions:

﻿$\begin{array}{rcl} \\[-1em] (x + 3)^{2} + 9 &=&0 \\[-1em] \\ \\[-1em] (x + 3)^{2} &=& -9 \\[-1em] \\ \\[-1em] x + 3 &=& \pm \sqrt{-9 }\\[-1em] \end{array}$﻿

1) Study the example. At what point did you realize the equation had no solutions?

2) Explain how you know the equation ﻿$49 + x^{2} = 0$﻿ has no solutions.

##### The Potato and the Pumpkin

The equation ﻿$h(t) = -16t^{2} + 80t + 64$﻿ represented the height, in feet, of a potato ﻿$t$﻿ seconds after it has been launched.

3) Write an equation that can be solved to find when the potato hits the ground.

4) Then solve the equation.

Show Work

5) Write an equation that can be solved to find when the potato is 40 feet off the ground.

6) Then solve the equation.

Show Work

The equation ﻿$g(t) = 2 + 23.7t - 4.9t^{2}$﻿ models the height, in meters, of a pumpkin ﻿$t$﻿ seconds after it has been launched from a catapult.

7) Is the pumpkin still in the air 8 seconds later?

True or false? Write below.

8) Explain or show how you know.

9) At what value of ﻿$t$﻿ does the pumpkin hit the ground?

##### Back to the Framer

Suppose you tried to frame a picture that was 7 inches by 4 inches using an entire sheet of paper that was 4 inches by 2.5 inches. One equation you could write to help you could be ﻿$(7+ 2x)(4 + 2x) = 38$﻿.

11) Explain or show what the equation ﻿$(7+ 2x)(4 + 2x) = 38$﻿ tells us about the situation and what it would mean to solve it. Use the diagram, as needed. 12) Solve the equation without graphing.